{"id":516,"date":"2011-10-02T03:39:30","date_gmt":"2011-10-02T08:39:30","guid":{"rendered":"http:\/\/www.journal-of-nuclear-physics.com\/?p=516"},"modified":"2011-10-02T08:24:18","modified_gmt":"2011-10-02T13:24:18","slug":"anomalous-mass-of-the-neutron","status":"publish","type":"post","link":"https:\/\/www.journal-of-nuclear-physics.com\/?p=516","title":{"rendered":"Anomalous mass of the neutron"},"content":{"rendered":"<p style=\"text-align: right;\"><em>by Wladimir Guglinski Mechanical Engineer graduated in the Escola de Engenharia da Universidade Federal de Minas Gerais- UFMG, (Brazil), 1973 author of the book Quantum Ring Theory-Foundations for Cold Fusion, published in 200<\/em><\/p>\n<p style=\"text-align: justify;\"><a href=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/Anomalous mass of the neutron.pdf\" target=\"_blank\">Direct download<\/a><\/p>\n<p style=\"text-align: justify;\">\n<p style=\"text-align: justify;\"><strong>Abstract<\/strong><br \/>\nA new model of the neutron n=p+s is proposed, where s is the selectron, a particle postulated by the Supersymmetry. \u00a0The model n=p+s belongs to the author\u2019s \u201cQuantum Ring Theory-Foundations for Cold Fusion\u201d, which is composed by 26 papers \u00a0published in a book form in 2006 by the Bauu Institute Press.<br \/>\nThe Nuclear Physics works with two models of the neutron. \u00a0The Yukawa&#8217;s model has several disadvantages (the most grave is the violation of the mass-energy conservation, although the theorists tried to justify it through the Heisenberg&#8217;s uncertainty principle), because his model cannot explain some phenomena. \u00a0The quark model (d,u,d) also cannot explain other sort of phenomena, and then the theorists use the two models, sometimes they use the Yukawa&#8217;s model, and sometimes they use the quark model. \u00a0However, they are two incompatible models, and it is difficult to believe that Nature works through the use of two incompatible models for the production of phenomena.<br \/>\nThe old Rutherford&#8217;s model of neutron has been abandoned by the theorists because it seems that it cannot be reconciled with some principles of Quantum Mechanics. \u00a0Nevertheless, herein it is shown that Rutherford&#8217;s model can be reconciled with the principles of QM when we introduce the hypothesis of the helical trajectory.<\/p>\n<p style=\"text-align: justify;\"><!--more--><strong> <\/strong><\/p>\n<p style=\"text-align: justify;\">Keywords: \u00a0new version n=p+s of Rutherford\u2019s neutron, Borghi and Conte-Pieralice experiments, Natarajan\u2019s helical trajectory incorporated to n=p+s, Borghi and Conte-Pieralice experiments suggesting a new Planck\u2019s gravitational constant, deuteron\u2019s quadrupole moment, neutron\u2019s magnetic moment, deuteron\u2019s magnetic moment.<\/p>\n<p style=\"text-align: justify;\"><strong>Introduction<\/strong><br \/>\nThis paper was submitted to several peer reviewed journals of Nuclear Physics. \u00a0All they rejected it. \u00a0In the last journal, the referee rejected it by claiming that a neutron cannot be formed by one proton and one selectron because the energy required to form a selectron is of about 20GeV. \u00a0However, 20GeV is the energy required from the current theories, which do not consider the helical trajectory of the electron. \u00a0So, a neutron formed by proton and selectron is impossible when it is considered by the current Nuclear Physics, but it is not impossible if we consider a model of electron with helical trajectory.<\/p>\n<p style=\"text-align: justify;\">The model of neutron proposed in the Quantum Ring Theory does not violate the Fermi-Dirac statistics, as it is explained as follows:<\/p>\n<ol style=\"text-align: justify;\">\n<li> In the present theory it is proposed that the elementary particles move through a helical trajectory (HT).<\/li>\n<li>In the author\u2019s paper [1], numbered No. 4 in his book, \u00a0it is shown that the HT has a property named Zoom-effect, according which the radius of the HT decreases with the growth of the velocity of the particle. \u00a0When the velocity is near to the velocity c of light, the radius of the HT tends to zero (which means that when an electron moves with relativistic speed, its motion approaches to a classical trajectory in the sense of Newton).<\/li>\n<li>In the author\u2019s paper [2], numbered No. 5 in his book, it is proposed that the spin of the particles (in the sense of quantum theory) is a result of the intrinsic spin of the particle combined with the rotation of the particle about the line center of its HT.<\/li>\n<li>So, as due to the Zoom-effect an electron with relativistic speed does not move through the HT, then an electron with relativistic speed becomes a boson, because it loses its quantum spin (which is a property of the HT, which vanished with the relativistic motion).<\/li>\n<li>In the present paper it is calculated the velocity of the electron about a proton, within the structure of the neutron. Its velocity is 92% of the light speed, which means that within the neutron\u2019s structure the electron becomes a boson.<\/li>\n<li>In the Supersymmetry it is postulated the existence of a particle with the same mass and charge of the electron, but with a null spin. \u00a0They call it selectron.<\/li>\n<li>So, we can consider that in the present theory the structure of the neutron actually is n=p+s, that is, the neutron is formed by one proton and one selectron. \u00a0Therefore the neutron actually is structured by one fermion (the proton) and one boson (the selectron).<\/li>\n<li>Then we realize that it is vanished the most grave restriction against the neutron formed by proton and electron, because now we can consider that the electron becomes a selectron within the neutron\u2019s structure. \u00a0Thereby such new structure fits to Fermi-Dirac\u2019s statistics, since in the new model n=p+s the neutron is formed by a fermion combined with a boson.<\/li>\n<\/ol>\n<p>So, as from the model of neutron n=p+s there is <span style=\"text-decoration: underline;\"><strong>no<\/strong><\/span> violation of Fermi-Dirac statistics, and since the other restrictions against n=p+s are eliminated in the present paper, then the theorists have no reason anymore for rejecting a model of neutron formed by one proton and one selectron.<br \/>\nThe mechanism according which an electron becomes a selectron within the structure n=p+s has been named \u201cspin-fusion\u201d in the author\u2019s theory. \u00a0Any lepton is subjected to be tied to a quark through the spin-fusion mechanism (within a structure with quark-lepton interaction we would rename the lepton by calling it \u201cselepton\u201d, which spin is zero).<br \/>\nA theoretical quark model of neutron n = (u,d,u-s) has been proposed by the author in a paper published by the Journal of New Energy [3], where it was shown that several paradoxes of Physics can be eliminated through the adoption of the new model. \u00a0As for example:<\/p>\n<ol style=\"text-align: justify;\">\n<li>From the proposal of the \u201cspin-fusion\u201d phenomenon the cause is found for the violation of the parity in beta-decay.\u00a0NOTE: The spin-fusion mechanism is proposed in the author&#8217;s paper &#8220;Stern-Gerlach Experiment and the Helical Trajectory&#8221;[2], and it is based on the property of the helical trajectory of the elementary particles, as proposed in the author&#8217;s paper &#8220;Fundamental Requirements for the Proposal of a New Hydrogen Atom&#8221;[1].<\/li>\n<li>From the new comprehension of the cause of violation of the parity, it is possible to propose a new interpretation for the temporal reversion (an interpretation of Christenson\u2019s discovery concerning the decay of some pions), in order that it is possible to eliminate the very strange hypothesis of temporal reversion in physics.<\/li>\n<\/ol>\n<p>The new model of neutron (u,d,u-s) can also supply theoretical backgrounds for the explanation of several questions arisen from new experimental findings, as we may mention for instance:<\/p>\n<ul style=\"text-align: justify;\">\n<li>a)\u00a0Taleyarkhan[4] experiment cannot be explained from the old concepts of Quantum Mechanics, since the Suslick-Didenko[5] experiment has shown that the greatest portion of the energy of the sonoluminescence phenomenon is wasted in chemical reactions, and therefore the remaining energy is unable to yield hot nuclear reactions.<\/li>\n<\/ul>\n<ul style=\"text-align: justify;\">\n<li>b)\u00a0New astronomical observations [6], described in the journal Nature, are suggesting that Planck\u2019s constant can have variation. \u00a0Such a hypothesis implies the breakdown of Quantum Mechanics, unless we show that for distances shorter than 2fm there are non-Coulombic interactions performed through a new sort of Planck\u2019s constant, which nature is gravitational.<\/li>\n<\/ul>\n<p>Before the acceptance of the model n=p+s by the scientists, there are several questions to be answered. Obviously the theoretical restrictions against the model n=p+e can also be applied to the model n=p+s (excluding the Fermi-Dirac statistics, as already explained before). \u00a0So, let us remember what are the restrictions against the model n=p+e.<br \/>\nOne of the solutions proposed herein is concerning the anomalous mass of the neutron.<br \/>\nThe repose mass of the proton and electron are:<\/p>\n<p>Proton: \u00a0m<em>P<\/em> = 938.3 MeV\/c\u00b2<br \/>\nElectron: \u00a0m<em>e<\/em> = 0.511MeV\/c\u00b2<br \/>\nTotal mass: m<em>T<\/em> = 938.811MeV\/c\u00b2<\/p>\n<p style=\"text-align: justify;\">A structure of the neutron n = p+e would have to have a mass m<em>N<\/em> &lt; 938.811 MeV\/c\u00b2, since there is a loss of mass. \u00a0However, it is known by experiments that neutron\u2019s mass is m<em>N<\/em> = 939.6MeV\/c\u00b2. \u00a0This fact is one of the stronger reasons why the majority of the physicists do not accept the model n=p+e, although several experiments have shown that neutron structure is indeed n=p+e. \u00a0So, herein we will show why the neutron with structure n = p+e has such an anomalous mass m<em>N<\/em>&gt;m<em>p<\/em>+m<em>e<\/em>.<br \/>\nAnother restriction against the model n = p+e comes from the Heisenberg\u2019s uncertainty principle: such a model requires a force with magnitude 10\u00b3\u00a0stronger than the strong nuclear force, in order to keep the electron in the nuclei. \u00a0Herein we propose a solution able to eliminate such a restriction.<br \/>\nConsidering the model n = p+e, the paper also exhibits the theoretical calculation for:<\/p>\n<p style=\"text-align: justify;\">a) \u00a0the magnetic moment of the neutron<br \/>\nb) \u00a0the electric quadrupole moment of the deuteron<br \/>\nc) \u00a0the magnetic moment of the deuteron<\/p>\n<p style=\"text-align: justify;\">NOTES:<\/p>\n<ol style=\"text-align: justify;\">\n<li>The helical trajectory of the elementary particles was proposed by Natarajan[7]. \u00a0According to his proposal, <em>\u201cWhen we consider a particle at rest in the laboratory frame, it has no external motion (vCX = 0). \u00a0The internal velocity, however, is given by vIN= c (Postulate 4). \u00a0On the other hand, if the particle is observed to be moving with a uniform velocity v in the laboratory (vCX = v), \u00a0then vIN should be vIN = (c\u00b2\u00a0&#8211; \u00a0v<em>\u00b2<\/em>)\u00bd\u00a0\u00a0so that the result of these two velocities is still c (Postulate 3 and 4).\u201d<\/em><\/li>\n<li>The helical trajectory appears in the Dirac\u2019s theory of the electron. \u00a0In their book[8] Lindsay and Margenau say:<em> <em>\u201cThe only possible resolution of this apparent paradox is to assume that the electron performs, in a classical sense, a rapidly periodic movement with the speed of light, while it progresses uniformly along x in conformity with (12). \u00a0Schr\u00f6dinger was the first to point out this peculiar trembling motion; \u00a0its actual significance is not clearly understood\u201d<\/em>.<\/em><\/li>\n<li>There is not any similar theory in the world. \u00a0The reason is obvious: \u00a0all the attempts of other theorists are made by considering the fundamental principles of quantum theory. \u00a0Nobody tries a model with a corpuscular electron, because all they consider that a corpuscular electron is incompatible with the Schr\u00f6dinger\u2019s Equation.<\/li>\n<\/ol>\n<p style=\"text-align: justify;\">Unlike, within the neutron\u2019s structure proposed here the electron is a corpuscular particle that moves through the helical trajectory, and so there is not any model of neutron similar to this model proposed herein.<br \/>\nOBS: \u00a0in the author\u2019s paper [1] it is shown that a corpuscular electron that moves through the helical trajectory is compatible with the Schr\u00f6dinger Equation. \u00a0This is the reason why the author can propose a model of neutron n=p+e where the electron is corpuscular, but other authors cannot do it.<br \/>\nDr. Rugero Santilli and Dr. Elio Conte have proposed a model of neutron n=p+e, but in their theory the electron is not corpuscular. \u00a0Their models are unable to explain fundamental questions that arrive when we try to propose a model n=p+e, as for example the violation of Fermi-Dirac statistics, the anomalous mass of the neutron, the magnitude of the neutron\u2019s magnetic moment (it would have to be in the same order of the electron\u2019s magnetic moment). \u00a0These questions are explained from the model \u00a0n=p+s.<\/p>\n<p style=\"text-align: justify;\">\n<p style=\"text-align: justify;\"><strong> Anomalous uncertainly principle<\/strong><br \/>\nAccording to current Particle Physics, the structure of the pion po is (d,d\u2019), where d is a quark (d)\u20131\/3 and d\u2019 is its antiparticle (d\u2019)+1\/3. The pion po can have two sorts of decays:<\/p>\n<p style=\"text-align: justify;\">\u03c7\u00ba \u2192 \u03b3 + \u03b3<br \/>\n\u03c7\u00ba \u2192 e+ + e- + proton \u00a0 \u00a0 \u00a0 (1)<\/p>\n<p style=\"text-align: justify;\">The time decay has the order of 10\u02c6-15s.<br \/>\nLet us calculate the binding energy necessary to pack together these two quarks d and d\u2019, considering the following:<\/p>\n<p style=\"text-align: justify;\">a) The quarks have a mass approximately 1\/2000 of the proton\u2019s mass<br \/>\nb) The Heisenberg\u2019s uncertainty principle \u00a0 \u00a0 \u00a0\u0394x.\u0394p ~ <em>h <\/em> (2)<\/p>\n<p style=\"text-align: justify;\">Consider the two quarks d and d\u2019 into a rectangular well with a radius \u201ca,\u201d where \u201ca\u201d is the distance between the two quarks into the structure of the pion\u00a0\u03c7\u00ba, in order that the uncertainty in the value of position is\u00a0\u0394x ~ a. \u00a0From Eq. (2) the smallest possible value of\u00a0\u0394p is given approximately by \u00a0\u0394p~<em>h<\/em>\/a. So, the quarks placed in the potential well of radius a\u22641fm would have kinetic energies, at least in the order of magnitude<\/p>\n<p style=\"text-align: justify;\">T ~ \u0394p\u00b2\/2\u00b5<em>\u03c0<\/em> ~ <em>h<\/em>\u00b2\/m<em>\u03c0<\/em>.a\u00b2\u00a0~ 80GeV \u00a0 \u00a0 \u00a0(3)<\/p>\n<p style=\"text-align: justify;\">where \u00b5<em>\u03c0<\/em> = m<em>\u03c0<\/em>\/2 \u00a0is the reduced mass of each quark.<\/p>\n<p style=\"text-align: justify;\">Let us expound the matter in another more precise way, by considering the conditions necessary for the appearance of a standing wave. For the rectangular potential well of the radius a, this condition is:<\/p>\n<p style=\"text-align: justify;\">2a = \u03bb\/2 \u00a0 \u00a0 (4)<\/p>\n<p style=\"text-align: justify;\">where\u00a0\u03bb is the de Broglie wavelength. Substituting \u00a0\u03bb = h\/p , \u00a0we have<\/p>\n<p style=\"text-align: justify;\">2a = h\/2p = h\/2(2\u00b5<em>\u03c0<\/em> T)\u00bd\u00a0= h\/2(m<em>\u03c0<\/em> T)\u00bd \u00a0 \u00a0 (5)<\/p>\n<p style=\"text-align: justify;\">where T is kinetic energy of the quark in the well. \u00a0From Eq. (5), with a \u22641fm, we have<\/p>\n<p style=\"text-align: justify;\">T = \u03c0\u00b22<em>h<\/em>\u00b2\/4m<em>\u03c0<\/em>a\u00b2 \u2265 180 GeV \u00a0 \u00a0 \u00a0(6)<\/p>\n<p style=\"text-align: justify;\">Since the two quarks are into the potential well along a time with the order of 10\u02c6\u201315s, it is necessary a depth of a well U<em>\u03c0<\/em> , as follows<\/p>\n<p style=\"text-align: justify;\">U<em>\u03c0<\/em> = T = \u00a0180 GeV \u00a0 \u00a0 (7)<\/p>\n<p style=\"text-align: justify;\">Let us compare it with the depth of potential well UN of deuteron nuclei, since we know that into the deuteron the proton and neutron are tied by the strong force. \u00a0The depth of the well UN is:<\/p>\n<p style=\"text-align: justify;\">U<em>N<\/em> = 40 MeV \u00a0 \u00a0 (8)<\/p>\n<p style=\"text-align: justify;\">\n<p style=\"text-align: justify;\">\n<div id=\"_mcePaste\" style=\"text-align: justify;\">Since Up \/UN = 4&#215;10\u00b3, this means that, for keeping the two quarks along the time 10\u02c6\u201315s, it would be necessary to have a force thousands times stronger than the nuclear force.<\/div>\n<div id=\"_mcePaste\" style=\"text-align: justify;\">Even if we consider the structure of the proton (u,d,u), two quarks &#8216;u&#8217; cannot be packed by the strong force into the potential well with radius a = 1fm. \u00a0It is necessary a force thousands times stronger than the nuclear force.<\/div>\n<div style=\"text-align: justify;\">Undoubtedly, this fact suggests that something is wrong with the uncertainty principle \u0394x.\u0394p ~ <em>h<\/em> into a potential well with radius a\u22641fm .<\/div>\n<div style=\"text-align: justify;\">\n<div>Besides, the decay shown in Eq. (1) shows that the bound state to the two quarks cannot be 180 GeV, and this suggests that something is wrong with the relation \u00a0\u0394x.\u0394p ~ <em>h<\/em> when we apply it for a potential well with radius a\u00a31fm.<\/div>\n<div>We will see ahead other fact suggesting that we cannot apply \u00a0\u0394x.\u0394p ~ <em>h<\/em> into a potential well with\u00a0a\u22641fm\u00a0.<\/div>\n<div>.<\/div>\n<\/div>\n<div style=\"text-align: justify;\"><strong>Gravitational quantum of energy<br \/>\n<\/strong>There are two experiments where the model \u00a0n = p+e has been obtained.<\/p>\n<div>In the 1980s, the physicist Don Borghi [2] et al. made an experiment where they obtained neutrons from protons and electrons at low energy. \u00a0At the end of the article they say, <em>\u201cHence we may conclude that this experiment seems to confirm the possibility of observing directly the assumed non-Coulombic interaction between protons and electrons.\u201d<\/em><\/div>\n<div>In 1999 the physicist Elio Conte, together with Maria Pieralice [3], made an experiment where they obtained neutrons from the cold fusion between protons and electrons.<\/div>\n<div>So, we have two different experiments where the researchers confirmed the structure n=p+e for the neutron.<\/div>\n<div>The mass of the electron is approximately the same mass of a quark d, both having a mass approximately 1\/2000 of the proton\u2019s mass. \u00a0This means that, into the structure n=p+e, the electron would have to be confined into a potential well with depth Ue = 180 GeV, that is, if we consider that we must apply the Heisenberg\u2019s relation (2). \u00a0And then it would require a kind of force thousands of times stronger than the nuclear force, in order to keep the electron in the structure n=p+e.<\/div>\n<\/div>\n<div style=\"text-align: justify;\">So, we have a dilemma:<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>On one side, Heisenberg\u2019s uncertainty principle \u00a0\u0394x.\u0394p ~ <em>h<\/em> imply that it is impossible a structure n=p+e.<\/li>\n<li>On the other side, two experiments are showing that n=p+e is the structure used by the Nature.<\/li>\n<\/ol>\n<\/div>\n<div style=\"text-align: justify;\">What have we to keep? We have two alternatives:<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>We keep the relation\u00a0\u0394x.\u0394p ~\u00a0<em>h<\/em>, and it means that we must reject the experiments. This is a betrayal to the scientific method.<\/li>\n<li>We keep the experiments, and this implies that we must analyze what happens with Heinsenberg\u2019s uncertainty principle into potential wells with a\u22641fm, because we must realize that something unknown by the physicists happens into regions with a\u22641fm.<\/li>\n<\/ol>\n<div>It is well to remember that in the beginning of the 20th Century several experiments suggested the structure n = p+e, as for example the neutron\u2019s decay \u2192\u00a0p+e+\u03bd&#8217;. \u00a0But Heisenberg rejected these experiments. \u00a0Since the Mathematics suggested that the structure n=p+e is impossible, Heisenberg decided to reject those old experiments.<\/div>\n<div>But now new experiments are showing that n=p+e is indeed correct. We cannot neglect the experiments anymore, like Heisenberg did. \u00a0This indicates that we must propose a new interpretation for the Heinsenberg\u2019s principle into a potential well with radius a\u22641fm.<\/div>\n<\/div>\n<div style=\"text-align: justify;\">First of all, let us remember that Planck\u2019s constant h = \u00a06.6&#215;10\u02c6\u201334J-s \u00a0has electromagnetic origin, since he made his experiments with photons into a black body. \u00a0But into a potential well with radius a\u22641fm, we have to consider the strong force. Then it is possible that Planck\u2019s constant must be replaced by a new constant hG , by considering that hG is a smallest quantum of energy due to the interactions by the nuclear force. \u00a0In the last item we will show that electron\u2019s bound energy into the neutron must have on the order of 0.1 MeV. \u00a0So, by considering that electron\u2019s binding energy has the order of \u00a00.1MeV, then, by introducing a correction, from Eq. (6) we get:<\/div>\n<div style=\"text-align: justify;\">h<em>G<\/em> ~ [ h\u00b2\/(180.000\/0,1) ]\u00bd\u00a0= 1,3&#215;10\u02c6-37J-s \u00a0 \u00a0 (9)<\/div>\n<div style=\"text-align: justify;\">One argument against this proposal is to say that the electron has no interaction by the strong force. However, in past papers the author will show that there are evidences suggesting that the strong force has gravitational origin, when we consider a dynamic gravity (different from the static gravity of current Physics).<\/div>\n<div style=\"text-align: justify;\">So, if we consider the quantum vacuum constituted by electromagnetic particles and by gravitons, through such a consideration it means that Planck\u2019s constant h is due to interactions by electromagnetic particles of the quantum vacuum, while the constant hG is due to interactions by gravitons.<\/div>\n<div style=\"text-align: justify;\">Pay attention that we are proposing here the constant hG through the same way as Planck proposed the constant h. \u00a0Indeed, Planck has been constrained to adopt the hypothesis of the constant h because that was the unique solution able to solve the paradox of the ultraviolet catastrophe into the black body. \u00a0By the same way, today we have two experiments, made by Borghi and by Conte, and these two experiments are showing that the neutron\u2019s structure is n=p+e. \u00a0The unique way to explain this structure, obtained by the experiments, is through the adoption of the following hypothesis:<\/div>\n<div style=\"text-align: justify;\">for a potential well with radius a<em>\u2264<\/em>1fm, \u00a0Heisenberg\u2019s uncertainty principle is \u00a0 \u0394x.\u0394p~h\u00a0, \u00a0where h<em>G<\/em>~1.3&#215;10\u02c6\u201337J-s \u00a0is the gravitational quantum of energy.<\/div>\n<div style=\"text-align: justify;\">.<\/div>\n<div style=\"text-align: justify;\"><strong>How to get the magnetic dipole moment of neutron<\/strong><br \/>\nMagnetic moment of the electron is by three orders of magnitude larger than that of the neutron. \u00a0So, at first glance, it seems that the neutron could not be performed by the structure n= p+e. \u00a0However, as is shown in the author&#8217;s other paper [7] , the magnetic moment of the electron depends on its helical trajectory into the electrosphere of the atom. \u00a0In another paper [8] , the author shows that the radius of the helical trajectory has vanished when the electron&#8217;s speed approaches light speed c. \u00a0So, in the structure n=p+e the electron&#8217;s speed is 0.92c , as we will calculate herein, then into the neutron the electron loses its helical trajectory, and by consequence its magnetic moment into the neutron is very small, justifying the present theoretical calculation for the neutron&#8217;s magnetic moment.<\/div>\n<div style=\"text-align: justify;\">Therefore the method of calculation is very simple:<\/div>\n<div style=\"text-align: justify;\">a)\u00a0The electron turning about the proton can be considered like a small spiral<br \/>\nb) The m of \u00a0neutron will be : \u00a0m<em>NEUTRON<\/em> = \u00a0m<em>PROTON<\/em> + m<em>SPIRAL<\/em><\/div>\n<div style=\"text-align: justify;\">Proton\u2019s magnetic moment we get from experiments, \u00b5\u00a0= +2,7896\u00b5n<\/div>\n<div style=\"text-align: justify;\">Spiral\u2019s magnetic moment we have to derive from calculation. We need to know two data about the electron\u2019s orbit:<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>Spiral\u2019s radius \u2013 we can get it from electron\u2019s orbit about two protons , starting from the electric quadrupole moment Q(b) of deuteron. From experiments, \u00a0Q(b) = + 2.7&#215;10\u02c6\u201331m\u00b2\u00a0, and from here we will get the radius R of the spiral.<\/li>\n<li>Electron\u2019s speed \u2013 we can get it from Kurie\u2019s graphic for beta-decay of neutron.<\/li>\n<\/ol>\n<\/div>\n<div style=\"text-align: justify;\"><strong>Proton&#8217;s radius<\/strong><br \/>\nWe will need proton\u2019s radius with more accuracy than Nuclear Theory can give us. And we will get it from recent interpretations about recent experiments. From Nuclear Theory, we know two important facts about the nucleus:<\/div>\n<div style=\"text-align: justify;\">\n<ul>\n<li>1st fact &#8211;\u00a0protons and neutrons have the same distribution into the nuclei. This conclusion had been inferred from interpretation about the empirical equation shown in the Fig. 1.<\/li>\n<li>2nd fact &#8211;\u00a0from the empirical equation, the physicists also concluded that all the nuclei have the same shell thickness \u00a0\u201c2b\u201d = 2 x 0.55F = 1.1F<\/li>\n<\/ul>\n<\/div>\n<div style=\"text-align: justify;\">From these two facts we can suppose that the protons and neutrons distribution into the nuclei is like shown in the Fig. 2, and thus we can get proton\u2019s radius:<\/div>\n<div style=\"text-align: justify;\">4 x Rp = 1.1F \u00a0\u2192\u00a0\u00a0 Rp = 0.275F \u00a0 \u00a0 \u00a0(10)<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">The radius Rp = 0.275F is corroborated by the proton&#8217;s distribution of load, obtained from experiments, shown in Fig. 10.<\/div>\n<div style=\"text-align: justify;\">We will verify that Rp = 0.275F can lead us to very good conclusions, according to the results of experiments.<\/div>\n<div style=\"text-align: justify;\">.<\/div>\n<div style=\"text-align: justify;\"><strong>Well-known calculation used by nuclear theory<br \/>\n<\/strong>Let us remember a theoretical calculation of electric quadrupole moment Q(b) used by Nuclear Theory.<\/p>\n<div style=\"text-align: justify;\">Fig. 3 shows a nucleus composed by a \u00a0[ magic number \u00a0+ \u00a01 proton ].<\/p>\n<div style=\"text-align: justify;\">For example, it can be the 51Sb<em>123<\/em> = 50Sn<em>122<\/em> + 1 proton. The magic number 50Sn122 \u00a0has Q(b)= 0, because its distribution is spherically symmetrical.<\/div>\n<\/div>\n<div style=\"text-align: justify;\">The 51Sb<em>123<\/em> will have<\/div>\n<\/div>\n<\/div>\n<div style=\"text-align: justify;\">Q(b) = \u00a0\u222b\u03c1\u00a0[ &#8211; (r\u2019 )\u00b2\u00a0].d\u03c4\u00a0= \u00a0-(r\u2019 )\u00b2. \u222b\u03c1.d\u03c4 \u00a0 \u00a0 \u00a0(11)<\/div>\n<div style=\"text-align: justify;\">But<\/div>\n<div style=\"text-align: justify;\">\u222b\u03c1.d\u03c4\u00a0\u00a0= \u00a0+ 1 \u00a0 \u00a0 \u00a0(12)<\/div>\n<div style=\"text-align: justify;\">because the ring (Fig. 3) \u00a0has 1 proton , and \u201c\u03c1\u201d is measured by proton\u2019s units of load.<\/div>\n<div style=\"text-align: justify;\">Consequently<\/div>\n<div style=\"text-align: justify;\">Q(b) = \u00a0 -(r\u2019)\u00b2 \u00a0 \u00a0 (13)<\/div>\n<div style=\"text-align: justify;\">This is a well-known traditional calculation. The nuclear physicists know it very well.<\/div>\n<div style=\"text-align: justify;\">.<\/div>\n<div style=\"text-align: justify;\"><strong>Application to the calculation of Q8b)<br \/>\n<\/strong>Let\u2019s apply this sort of considerations to the model of 1H2 shown in the Fig. 4, with one electron turning about two protons.<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">The two protons have Q(b) = 0 , because theirs distribution of load is spherically symmetrical. The electron can be considered like a proton with negative load, with punctual concentrated configuration, and therefore the electron produces a ring like shown in Fig. 5.<\/div>\n<div style=\"text-align: justify;\">If a proton with positive load yields \u00a0\u222b\u03c1d\u03c4\u00a0\u00a0= +1 , the electron with negative load yields \u00a0\u222b\u03c1d\u03c4\u00a0\u00a0= -1. By consequence, the \u00a0electric quadrupole moment of \u00a01H<em>2 <\/em> will be :<\/div>\n<div style=\"text-align: justify;\">Q(b) = -(r\u2019 )\u00b2\u222b\u03c1d\u03c4\u00a0= -(r\u2019 )\u00b2.(-1) = +(r\u2019 )\u00b2 \u00a0 \u00a0 \u00a0(14)<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">But \u00a0r\u2019= 2Rp (Fig. 4) , and Rp = 0.275F is the proton\u2019s radius obtained in (10).<\/div>\n<div style=\"text-align: justify;\">Thereby:<\/div>\n<div style=\"text-align: justify;\">Q(b) = \u00a0+(r\u2019 )\u00b2\u00a0= +(0,55F)\u00b2\u00a0= +3,0&#215;10\u02c6-31m\u00b2 \u00a0 \u00a0 \u00a0(15)<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">But the radius Rp = 0.275F is not exact, because it is obtained by experiments ( b = 0.55F ).<\/div>\n<div style=\"text-align: justify;\">If we consider \u00a0Rp = 0.26F, we will have \u00a0r\u2019 = 0.52F, and then:<\/div>\n<div style=\"text-align: justify;\">Q(b) = +(0.52F)\uf020Q(b)\u00b2\u00a0= + 2.7 x 10\u02c6-31m\u00b2 \u00a0 \u00a0 \u00a0(16)<\/div>\n<div style=\"text-align: justify;\">like inferred from experiments, and therefore we can take R = 0.26F (spiral\u2019s radius).<\/div>\n<div style=\"text-align: justify;\">NOTE: \u00a0Of course Yukawa\u2019s model cannot explain Q(b) = +2.7 x 10\u02c6-31m\u00b2\u00a0of deuteron, because the two protons have Q(b) = 0, and the meson\u2019s oscillation cannot be responsible by \u00a0Q(b) = +2.7 x 10\u02c6-31m\u00b2. \u00a0A deuteron performed by (u,d,u).(d,u,d) of current Nuclear Physics also cannot get the result Q(b)= +2.7&#215;10\u02c6-31m\u00b2\u00a0of the experiments.<\/div>\n<div style=\"text-align: justify;\">\n<p><strong>Electron&#8217;s speed<br \/>\n<\/strong>We will get electron\u2019s speed from the neutron\u2019s beta-decay (Fig. 9).<\/p>\n<\/div>\n<div style=\"text-align: justify;\">Electron\u2019s repose energy ( E = m<em>0<\/em>.c\u00b2\u00a0) \u00a0is \u00a00.511 MeV.<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">From Kurie\u2019s graphic interpretation, electron\u2019s kinetic energy Ke<em>MAX<\/em> when emitted in the beta-decay, corresponds to the binding energy 0.78 MeV , that is, electron\u2019s kinetic energy turning about the proton.<\/div>\n<div style=\"text-align: justify;\">0.78MeV &gt; 0.511MeV, \u00a0by consequence \u00a0E<em>KINETIC<\/em> &gt; m<em>0<\/em>.c\u00b2, and therefore we need to apply Einstein\u2019s Relativistic dynamics if we want to know electron\u2019s \u201cv\u201d speed in the spiral.<\/div>\n<div style=\"text-align: justify;\">The relativistic kinetic energy is \u00a0:<\/div>\n<\/div>\n<div style=\"text-align: justify;\">E = m<em>0<\/em>.c\u00b2[ 1\/( 1 &#8211; v\u00b2\/c\u00b2\u00a0)\u00bd\u00a0-1 ] \u00a0 \u00a0 \u00a0(17)<\/div>\n<div style=\"text-align: justify;\">Thus, we have:<\/div>\n<div style=\"text-align: justify;\">0.78MeV = 0.511MeV[ 1\/( 1- v\u00b2\/c\u00b2\u00a0)\u00bd\u00a0-1 ] \u00a0 \u00a0 \u00a0(18)<\/div>\n<div style=\"text-align: justify;\">\u03bb\u00a0= 1\/( 1- v\u00b2\/c\u00b2\u00a0)\u00bd\u00a0= \u00a02.5264 \u00a0 \u00a0 \u00a0(19)<\/div>\n<div style=\"text-align: justify;\">1\/( 1-\u00a0v\u00b2\/c\u00b2\u00a0) \u00a0 = \u00a06.383 \u00a0 \u00a0 \u00a0(20)<\/div>\n<div style=\"text-align: justify;\">6.383 &#8211; 6.383.v\u00b2\/c\u00b2\u00a0\u00a0= 1 \u00a0 \u00a0 \u00a0 (21)<\/div>\n<div style=\"text-align: justify;\">6.383 \u00d7\u00a0v\u00b2\/c\u00b2\u00a0 = \u00a05.383 \u00a0 \u00a0 \u00a0(22)<\/div>\n<div style=\"text-align: justify;\">v = c (5.383\/6.383)\u00bd\u00a0\u00a0= \u00a02.746&#215;10\u02c68 m\/s \u00a0 ~ \u00a0 91.83% c \u00a0 \u00a0 (23)<\/div>\n<div style=\"text-align: justify;\">A spiral with area \u201cA\u201d , a current \u201ci\u201d , and radius R , produces<\/div>\n<div style=\"text-align: justify;\">\u00b5\u00a0= i.A = q.v.\u03c0.R\u00b2\/ 2\u00b5R \u00a0= \u00a0q.v.R\/2<\/div>\n<div style=\"text-align: justify;\">and with relativistic speeds<\/div>\n<div style=\"text-align: justify;\">\u00b5\u00a0= q.v.R \u00a0 \u00a0 \u00a0(24)<\/div>\n<div style=\"text-align: justify;\">The magnetic dipole moment\u00a0\u00b5<em>SPIRAL<\/em> of one relativistic spiral will suffer a correction proportional to:<\/div>\n<div style=\"text-align: justify;\">\u03bb\u00a0= 1\/( 1-\u00a0v\u00b2\/c\u00b2\u00a0)\u00bd \u00a0 \u00a0 (25)<\/div>\n<div style=\"text-align: justify;\">because if \u00a0v\u2192c \u00a0, \u00a0 then \u00a0 \u00a0\u00b5<em>SPIRAL<\/em>\uf020 \u2192 \u221e.<\/div>\n<div style=\"text-align: justify;\">\u00b5<em>SPIRAL<\/em> = q.v.R\/[ ( 1-\u00a0v\u00b2\/c\u00b2\u00a0)\u00bd\u00a0] , \u00a0 when \u00a0 v \u2192\u00a0c \u00a0 \u00a0 (26)<\/div>\n<div style=\"text-align: justify;\">R = spiral\u2019s radius \u00a0= \u00a00.26F \u00a0<span style=\"white-space: pre;\"> <\/span>(27)<\/div>\n<div style=\"text-align: justify;\">q = -1.6&#215;10\u02c6-19C \u00a0 \u00a0 \u00a0(28)<\/div>\n<div style=\"text-align: justify;\">v = 2.746&#215;10\u02c68 m\/s \u00a0 \u00a0 \u00a0(29)<\/div>\n<div style=\"text-align: justify;\"><em><span style=\"font-style: normal;\">\u00b5<\/span>SPIRAL<\/em>\uf020\uf020 = \u00a0\u03bb.[q.v.R] \u00a0 \u00a0 , \u00a0 \u00a0\u03bb\u00a0= 2.5264 \u00a0in the present problem \u00a0 \u00a0\u00a0(30)<\/div>\n<div style=\"text-align: justify;\"><em><span style=\"font-style: normal;\">\u00b5<\/span>SPIRAL<\/em> = 2.5264 x (-1.6 x 10\uf020\uf020\uf020\u02c6-19C) x 2.746 x 10\u02c68m\/s x 0.26 x 10\u02c6-15m \u00a0 \u00a0\u00a0(31)<\/div>\n<div style=\"text-align: justify;\"><em><span style=\"font-style: normal;\">\u00b5<\/span>SPIRAL<\/em> = 2.886 x 10\u02c6\u201326 A-m\u00b2\u00a0= \u00a0-5.715<em><span style=\"font-style: normal;\">\u00b5<\/span><\/em>n \u00a0 \u00a0\u00a0(32)<\/div>\n<div style=\"text-align: justify;\">.<\/div>\n<div style=\"text-align: justify;\"><strong>Calculation of the magnetic dipole moment of neutron<\/strong><br \/>\nThe proton has\u00a0\u00b5\u00a0= +2.7896mn , and then the magnetic dipole moment of neutron will be:<\/div>\n<div style=\"text-align: justify;\">\u00b5<em>NEUTRON<\/em> = +2.7896 &#8211; 5.715 = -2.9254\u00b5n \u00a0 \u00a0 \u00a0(33)<\/div>\n<div style=\"text-align: justify;\">and the experiments detected -1.9103mn.<\/div>\n<div style=\"text-align: justify;\">This result is coherent, if we consider:<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>The radius R= 0.26F has been obtained from the calculation of electric quadrupole moment, and therefore it is necessary to consider an external radius due to the electron\u2019s orbit around the proton,<br \/>\nRext = 0.26F \u00a0 \u00a0 \u00a0(34)<br \/>\nbecause the <span style=\"text-decoration: underline;\">external<\/span> radius is responsible by the measurement of \u00a0Q(b).<\/li>\n<li>In the spiral\u2019s area responsible by the magnetic dipole moment, it is necessary to consider the internal spiral\u2019s radius,<br \/>\nRint = Rext &#8211; \u03a6e \u00a0(\u03a6e = electron\u2019s diameter) \u00a0 \u00a0 \u00a0(35)<br \/>\nbecause the \u201cinternal area\u201d of the spiral produces the flux of magnetic dipole moment.<\/li>\n<\/ol>\n<p>The experiments already detected electron\u2019s radius, which magnitude is smaller than 10\u02c6-16m , and also proton\u2019s radius, in order of 10\u02c6-15m . Therefore, we can conclude that the density of their masses is approximately the same, because the relation between their masses is:<\/p>\n<\/div>\n<div style=\"text-align: justify;\">983.3MeV \/c\u00b2\u00a0\/ 0.511MeV \/c\u00b2\u00a0\u00a0 = \u00a0 1836 \u00a0 \u00a0 (36)<\/div>\n<div style=\"text-align: justify;\">and the relation between theirs radii is:<\/div>\n<div style=\"text-align: justify;\">Rp \/ Re = (1836 )\u02c61\/3\u00a0\u00a0= \u00a012,25 \u00a0~ 10\u02c6-15 \/10\u02c6-16m \u00a0 \u00a0 (37)<\/div>\n<div style=\"text-align: justify;\">Rp ~ 0.26F \u00a0\u2192\u00a0\u00a0Re ~ \u00a00.26 \/ 12.25 \u00a0= \u00a00.0212F \u00a0 \u00a0\u00a0(38)<\/div>\n<div style=\"text-align: justify;\">Thus, electron\u2019s diameter is \u03a6e = 2 x 0.0212F = 0.0424F \u00a0, \u00a0and the internal radius of spiral will be:<\/div>\n<div style=\"text-align: justify;\">Rint = 0.26F \u2013 0.0424F \u00a0= \u00a0 0.2176F \u00a0 \u00a0 (39)<\/div>\n<div style=\"text-align: justify;\">The correct magnetic dipole moment of electron\u2019s spiral will be:<\/div>\n<div style=\"text-align: justify;\">\u00b5<em>SPIRAL<\/em> = -5.715 x 0.2176 \/ 0.26 = -4.783\u00b5n \u00a0 \u00a0 (40)<\/div>\n<div style=\"text-align: justify;\">and we get<\/div>\n<div style=\"text-align: justify;\">\u00b5NEUTRON = -4.783 + 2.7896 = -1.9934\u00b5n \u00a0 \u00a0 (41)<\/div>\n<div style=\"text-align: justify;\">which is a very good result.<\/div>\n<div style=\"text-align: justify;\"><strong>Magnetic dipole moment of deuteron<\/strong><br \/>\nThe proton has\u00a0\u00b5<em>\u03c1<\/em> = +2.7896\u00b5n, and the neutron has\u00a0\u00b5<em>N<\/em> = -1.9103mn. \u00a0Then let us see what magnetic moment for the deuteron we would have to expect from the current theories of Physics.<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>From Yukawa\u2019s model, as the meson has oscillatory motion between the proton and the neutron, it cannot produce any additional magnetic moment. \u00a0Therefore from Yukawa\u2019s model the magnetic moment of deuteron would have to be mD = +2.7896\u00b5n &#8211; 1.9103\u00b5n = + 0.8793\u00b5n.<\/li>\n<li>From the model of Particle Physics (u,d,u)(d,u,d) there is no reason why an additional magnetic moment can be created. \u00a0Then we also would have to expect \u00b5<em>D<\/em> = +0.8793\u00b5n.<\/li>\n<\/ol>\n<\/div>\n<div style=\"text-align: justify;\">But the experiments show that the deuteron has magnetic moment\u00a0\u00b5<em>D<\/em> = \u00a0+0.857\u00b5n. \u00a0So, from the models of neutron used in current Physics is impossible to explain the magnetic moment of deuteron. \u00a0Let us see if we can explain it from the present model of neutron n = p+e.\u00a0In the formation of the deuteron, there are two protons with the same spin, so the spin due to the protons is i=1. \u00a0In the First Part of the paper New Model of Neutron [1] we already have seen that electron\u2019s contribution is null for the total spin, as consequence of the spin-fusion phenomenon. \u00a0Therefore the deuteron has nuclear spin i=1.<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">Calculation of\u00a0\u00b5.<\/div>\n<div style=\"text-align: justify;\">Fig. 6 illustrates the method:<\/div>\n<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>There are two protons each one with mp= +2.7896\u00b5n.<\/li>\n<li>We already obtained spiral\u2019s \u00a0\u00b5S= -4.783\u00b5n. \u00a0But we will consider\u00a0\u00b5<em>S<\/em>= -4.7mn , because 0.083 is due to error in the accuracy.<\/li>\n<li>When the electron of the structure n = p+e is situated between the two protons of the structure of the deuteron (see Fig. 6), it is submitted to three forces:<br \/>\na) The nuclear force of attraction with the proton into the neutron\u2019s structure (proton at right side).<br \/>\nb) The centrifugal force expelling the electron in the direction of the proton at the left side.<br \/>\nc) The nuclear force of attraction with the proton at the right side.<\/li>\n<\/ol>\n<div style=\"text-align: justify;\">Then there is an increase of area \u0394A due to the electron\u2019s deviation in the direction of the proton at the left side, which is responsible for an increase of\u00a0\u0394\u03bc\u00a0.<\/div>\n<div style=\"text-align: justify;\">We can approach the area\u00a0\u0394A\u00a0of Fig. 6 from a rectangular area, as shown in Fig. 7, and the total magnetic moment will be performed as indicated in the Fig. 8.<\/div>\n<div style=\"text-align: justify;\">We know that electron\u2019s SPIRAL has a radius R = 0.26F.<\/div>\n<div style=\"text-align: justify;\">Let us consider that\u00a0\u0394A\u00a0is a rectangular area with dimensions 0.52F and 0.002F. \u00a0Then the area is:<\/div>\n<\/div>\n<div style=\"text-align: justify;\">\u0394A = 0.52 x 0.002 = 0.001F\u00b2\u00a0\u00a0 \u00a0 (42)<\/div>\n<div style=\"text-align: justify;\">The area of electron\u2019s spiral is:<\/div>\n<div style=\"text-align: justify;\">A = \u00a0p.0.26\u00b2\u00a0= 0.212 F\u00b2\u00a0\u00a0 \u00a0 (43)<\/div>\n<div style=\"text-align: justify;\">If the spiral with area A = 0.212 F\u00b2\u00a0\u00a0produces m= -4.7\u00b5n , then an area \u00a0\u0394A = 0.001F\u00b2\u00a0\u00a0will produce:<\/div>\n<div style=\"text-align: justify;\">\u0394\u00b5\u00a0= -4.7 x 0.001\/0.212 = -0.022\u00b5n \u00a0 \u00a0\u00a0(44)<\/div>\n<div style=\"text-align: justify;\">and \u00a0the theoretical\u00a0\u00b5\u00a0of \u00a01H<em>2<\/em>, obtained from the model n = p+e, will be:<\/div>\n<div style=\"text-align: justify;\">2.(+2.7896) \u2013 (4.7 + 0.022) = +0.857\u00b5n \u00a0 \u00a0 (45)<\/div>\n<div style=\"text-align: justify;\"><strong>Anomalous mass of the neutron<\/strong><br \/>\nWe will show that neutron\u2019s anomalous mass is due to the growth of the electron\u2019s mass, since the electron has a relativistic speed into the neutron, as we will calculate here. So, let us calculate the electron\u2019s increase of mass.<\/div>\n<div style=\"text-align: justify;\">The electron\u2019s mass into the neutron n=p+e \u00a0is:<\/div>\n<div style=\"text-align: justify;\">m = m<em>o<\/em>.\u03b3 \u00a0 \u00a0 \u00a0(46)<\/div>\n<div style=\"text-align: justify;\">where\u00a0\u03b3\u00a0we already obtained in (30): \u00a0\u00a0\u03b3\u00a0= 2.5264<\/div>\n<div style=\"text-align: justify;\">So<\/div>\n<div style=\"text-align: justify;\">m = m<em>o<\/em>.\u03b3\u00a0= 0.511 x 2.5264 = \u00a01.291 MeV\/c\u00b2 \u00a0 \u00a0 \u00a0(47)<\/div>\n<div style=\"text-align: justify;\">Considering the electron\u2019s increase of mass, the proton and the electron perform the total mass:<\/div>\n<div style=\"text-align: justify;\">m<em>p<\/em> + m<em>e<\/em> = 938.3 MeV\/c\u00b2\u00a0+ 1.291 MeV\/c\u00b2\u00a0= 939.591 MeV\/c\u00b2\u00a0~ 939.6 MeV\/c\u00b2 \u00a0 \u00a0\u00a0(48)<\/div>\n<div style=\"text-align: justify;\">\n<div style=\"text-align: justify;\">Since m<em>p<\/em> + m<em>e<\/em> ~ 939.6 MeV\/c\u00b2\u00a0, and the neutron\u2019s mass is m<em>N<\/em> = 939.6 MeV\/c\u00b2, we realize that neutron\u2019s binding energy is approximately zero, and this explains why it suffers decay. \u00a0However, with more accurate experiments, perhaps it is possible to discover the correct binding energy of the neutron. \u00a0So, by more accurate experiments, we can get the correct value of hG obtained in Eq. (9).<\/div>\n<div style=\"text-align: justify;\">.<\/div>\n<div style=\"text-align: justify;\"><strong>Conclusions<\/strong><\/div>\n<div style=\"text-align: justify;\">The first reaction of a physicist against the proposals of the present paper probably would be to claim the following: <em> &#8220;It is hard for me to believe those difficulties raised in this manuscript will have escaped the scrutiny of all those prominent particle theorists. For instance, the author proposes a new Planck constant for the uncertainty principle in the femtometer scale. \u00a0Had this been true, the string theorists should have encountered the difficulty long time ago and even have proposed their own third different Planck constant.&#8221;<\/em><\/div>\n<div style=\"text-align: justify;\">We must analyze such an argument from five viewpoints, as follows:<\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>First viewpoint: Up to know the theoretists have neglected the Borghi&#8217;s experiment, and this is just the reason why they never tried such a new theoretical alternative. Indeed, the proposal of a new Planck&#8217;s constant, proposed herein, is required by the results of two new experiments, made by Conte-Pieralice and Borghi. Even if the present new proposal is not a definitive solution, nevertheless any other different solution must be proposed by considering the results of Conte-Pieralice-Borghi experiments. \u00a0By neglecting their experiments is impossible to find a satisfactory solution.<br \/>\nMoreover, it is well to note that the proposal of a new Planck\u2019s constant is not able to solve the theoretical problems itself. \u00a0That\u2019s why such an idea has never been proposed by the string theorists, since such new proposal actually must be proposed together with other new proposals, like the spin-fusion hypothesis, the helical trajectory, its zoom-property[8], etc. \u00a0The new Planck\u2019s constant is not proposed here alone, actually it belongs to a collection of new proposals that performs new principles (which are missing in Quantum Mechanics).<\/li>\n<li>Second viewpoint: The recent new experiment made by Taleyarkhan, published by Science, has been explained by the scientific community as follows: <em>\u201cTheoretical explanations for the observation of neutrons in line with conventional theory do exist. Sonoluminescence is an observed and understood phenomenon. It is generally considered to be theoretically possible to generate fusion temperatures in imploding bubbles using sound. As for tunnelling through the Coulomb barrier at low temperatures, so as to achieve fusion at low temperatures, this could have been possible in principle, but experts who did the calculation say that, unfortunately, the rate will be far too slow to be observable, let alone be of any practical importance\u201c<\/em>. Nevertheless, Suslick and Didenko have repeated the Taleyarkhan experiment, and they have shown that the greatest portion of the sonoluminescence energy is wasted in chemical reactions. Therefore it is not possible to suppose that there are hot nuclear reactions in Taleyarkhan experiment. And since he obtained emission of neutrons (and therefore the existence of nuclear reactions is out of any doubt), we realize that these nuclear reactions cannot be explained by the old concepts of Quantum Mechanics. We must explain Taleyarkhan experiment from the hypothesis of non-Coulombic interactions, detected by Borghi\u2019s experiment.<\/li>\n<li>Third viewpoint: In the present paper a new gravitational Planck\u2019s constant has been proposed, taking in consideration the Borghi\u2019s experiment. \u00a0A paper published in the journal Nature in August-2002, by Paul Davies corroborates such a hypothesis, in which he says that a new astronomical observation can lead to the conclusion that the Theory of Relativity may be wrong. The observation considered by Dr. Paul Davies is concerning the interaction between electrons and photons, and the results led him to consider two alternatives, as follows:<br \/>\na) FIRST HYPOTHESIS: The light velocity &#8220;c&#8221; is not constant<br \/>\nb) SECOND HYPOTHESIS: The Planck&#8217;s constant can have some variation<br \/>\nWell, it is possible that such a variation in the Planck\u2019s constant, mentioned by Paul Davies, can be actually due to the interaction with the \u00a0new gravitational Planck\u2019s constant proposed herein.<\/li>\n<li>Fourth viewpoint: It must be taken in consideration that the &#8220;spin-fusion&#8221; hypothesis is able to open new theoretical perspectives for the Particle Physics, through the establishment of a new Standard Model, as shown in the author&#8217;s paper &#8220;New Model of Neutron-First Part&#8221;,( 1 ) published by JNE, where it is shown that the lepton\u2019s spin is not conserved in the beta-decay. Since the leptons are tied to the quarks through the spin-fusion, as proposed by the author, such a new proposal represents a new fundamental concept to be applied to Nuclear Theory and to Particle Physics.<\/li>\n<li>Fifth viewpoint: The theorists are trying since 1950 to find a satisfactory theory able to conciliate the several branches of Physics. Several genii as Einstein, Dirac, Heisenberg, and others, devoted their life to the attempt. \u00a0The problem has passed through the hand of several prominent physicists, among them several ones awarded the Nobel Prize and devoted their work to the question of the unification, as Salam, Gell-Mann, Weinberg , Glashow, t&#8217;Hooft, and others. All they have supposed that the rule of addition of spins, adopted in current Nuclear Physics, is the correct theoretical way. <strong>However, it is hard to believe that a satisfactory solution should have escaped the scrutiny of all those prominent theoretists, if such a solution should be possible by the way that they are trying<\/strong> (up to now there is not a satisfactory Standard Model in Particle Physics, which is incompatible with the Nuclear Physics, a theory itself not able to explain several questions). If a satisfactory solution via the Yukawa model should be possible, of course that it would have to be found several years ago.<\/li>\n<\/ol>\n<\/div>\n<div style=\"text-align: justify;\">A new model can replace an old one only if the new one brings advantages. The Yukawa&#8217;s model has several disadvantages, but the author considers that the most serious is the fact that in Modern Physics the description of the phenomena must be made through the consideration of two incompatible models: some phenomena must be described by the quark model of neutron, and others must be described by Yukawa&#8217;s model, but they are incompatible. It makes no sense to believe that in the Nature two incompatible models must describe the phenomena. \u00a0The author&#8217;s model (u,d,u-e) is able to describe all the phenomena and properties of the neutron, and perhaps this is the greatest advantage of the model.<\/div>\n<div style=\"text-align: justify;\">Finally, we have to consider that, when a new experiment has a result that does not fit the current prevailing concepts of an old theory, the scientific criteria prescribes that the theoretists must try to find a new theoretical solution able to explain the result obtained by the new experiment, through the proposal of new concepts. This is just what the author of the model (u,d,u-e) is trying to do. \u00a0Nevertheless, nowadays the theoretists are trying to keep the old prevailing concepts of Quantum Mechanics by rejecting the Borghi&#8217;s experiment, and such a rejection does not fit the scientific criteria.<\/div>\n<div style=\"text-align: justify;\"><strong>References<\/strong><\/div>\n<div style=\"text-align: justify;\">\n<ol>\n<li>W. Guglinski, &#8220;New Model of Neutron-First Part,&#8221; \u00a0<em>J. New Energy<\/em>, vol 4, no 4, 2000.<\/li>\n<li>C. Borghi, C. Giori, A.A. Dall\u2019Ollio, &#8220;Experimental Evidence of Emission of Neutrons from Cold Hydrogen Plasma,&#8221; <em>American Institute of Physics<\/em> (Phys. At. Nucl.), vol 56, no 7, 1993.<\/li>\n<li>E. Conte, M. Pieralice, &#8220;An Experiment Indicates the Nuclear Fusion of the Proton and Electron into a Neutron,&#8221; <em>Infinite Energy<\/em>, vol 4, no 23-1999, p 67.<\/li>\n<li>R.P. Taleyarkhan, C.D. West, J.S. Cho, R.T. Lahey, Jr., R.I. Nigmatulin, and R.C. Block, &#8220;Evidence for Nuclear Emissions During Acoustic Cavitation,&#8221; <em>Science<\/em>, vol 295, pp 1868-1873 (March 8, 2002) (in Research Articles).<\/li>\n<li>Y.T. Didenko, K. S. Suslick, &#8220;The energy efficiency of formation of photons, radicals and ions during single-bubble cavitation,&#8221; <em>Nature<\/em>, vol 418, 394 &#8211; 397 (25 Jul 2002) Letters to Nature.<\/li>\n<li>P.C.W. Davies, Tamara M. Davis, Charles H. Lineweaver, &#8220;Cosmology: Black holes constrain varying constants,&#8221; <em>Nature<\/em>, vol 418, pp 602 &#8211; 603 (08 Aug 2002) Brief Communication.<\/li>\n<li>W. Guglinski, &#8220;Stern-Gerlach Experiment and the Helical Trajectory&#8221; <em>J. New Energy<\/em>, vol 7, no 2.<\/li>\n<li>W. Guglinski, &#8220;Fundamental Requirements for the Proposal of a New Hydrogen Atom,&#8221; <em>J. New Energy<\/em>, vol 7, no 2, 2004.<\/li>\n<\/ol>\n<\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 01\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure01.gif\" alt=\"\" width=\"365\" height=\"293\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 02\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure02.gif\" alt=\"\" width=\"180\" height=\"209\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 03\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure03.gif\" alt=\"\" width=\"184\" height=\"188\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 04\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure04.gif\" alt=\"\" width=\"165\" height=\"157\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 05\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure05.gif\" alt=\"\" width=\"195\" height=\"157\" \/><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 06\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure06.gif\" alt=\"\" width=\"152\" height=\"123\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 07\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure07.gif\" alt=\"\" width=\"152\" height=\"115\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 08\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure08.gif\" alt=\"\" width=\"186\" height=\"155\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 09\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure09.gif\" alt=\"\" width=\"289\" height=\"242\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><img loading=\"lazy\" class=\"aligncenter\" title=\"Figure 10\" src=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/images\/21-figure10.gif\" alt=\"\" width=\"196\" height=\"167\" \/><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><\/div>\n<div style=\"text-align: justify;\"><a href=\"https:\/\/www.journal-of-nuclear-physics.com\/files\/Anomalous mass of the neutron.pdf\" target=\"_blank\">Direct download<\/a><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p style=\"text-align: right;\">by Wladimir Guglinski Mechanical Engineer graduated in the Escola de Engenharia da Universidade Federal de Minas Gerais- UFMG, (Brazil), 1973 author of the book Quantum Ring Theory-Foundations for Cold Fusion, published in 200<\/p>\n<p style=\"text-align: justify;\">Direct download<\/p>\n<p style=\"text-align: justify;\">\n<p style=\"text-align: justify;\">Abstract A new model of the neutron n=p+s is proposed, where [&#8230;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[3],"tags":[],"_links":{"self":[{"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/posts\/516"}],"collection":[{"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=516"}],"version-history":[{"count":38,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/posts\/516\/revisions"}],"predecessor-version":[{"id":518,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=\/wp\/v2\/posts\/516\/revisions\/518"}],"wp:attachment":[{"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=516"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=516"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.journal-of-nuclear-physics.com\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=516"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}